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Friday, September 24, 2021

Tugas Pertemuan 2 Jaringan Komputer

Hitunglah jumlah Network dan Host yang akanterbentuk dari alamat IP Address dibawah ini, kemudian buat rincian alamat (Network, Broadcast) beserta alamat yang dapat diberikan kepada setiap host (minimal untuk 5 host/komputer):
1. 192.168.10.1/30
2. 172.168.10.1/16
3. 172.168.10.0/22
4. 10.168.5.1/8
5. 10.168.5.1/17
Jawab :

1) 192.168.10.1/30
Netmask = 255.255.255.252
Subnet    = 11111111.11111111.11111111.11111100 : /30
Network = 2n = 26 = 64 network
Host       = 2h-2 = 22-2 = 2 host

Alokasi IP :
Network   : 192.168.10.0
Host         : 192.168.10.1 - 192.168.10.2
Broadcast : 192.168.10.3

Network   :192.168.10.4
Host         : 192.168.10.5 - 192.168.10.6
Broadcast : 192.168.10.7

Network   :192.168.10.8
Host         : 192.168.10.9 - 192.168.10.10
Broadcast : 192.168.10.11

2) 172.168.10.1/16
Netmask = 255.255.000.000
Subnet    = 11111111.11111111.00000000.00000000 : /16
Network = 2n = 20 = 1 network
Host       = 2h-2 = 216-2 = 65.534 host

Alokasi IP :
Network   :172.168.0.0
Host         : 172.168.0.1 - 192.168.255.254
Broadcast : 192.168.255.255

3) 172.168.10.0/22
Netmask = 255.255.252.000
Subnet    = 11111111.11111111.11111100.00000000 : /22
Network = 2n = 26 = 64 network
Host       = 2h-2 = 210-2 = 1.022 host

Alokasi IP :
Network   :172.168.10.0
Host         : 172.168.10.1 - 192.168.255.254
Broadcast : 192.168.255.255

4) 10.168.5.1/8
Netmask = 255.000.000.000
Subnet    = 11111111.00000000.00000000.00000000 : /8
Network = 2n = 20 = 1 network
Host       = 2h-2 = 224-2 = 167.772.614 host

Alokasi IP :
Network   :10.168.5.0
Host         : 10.0.0.1 - 10.255.255.254
Broadcast : 10.255.255.255

5) 10.168.5.1/17
Netmask = 255.255.128.000
Subnet    = 11111111.11111111.10000000.00000000 : /17
Network = 2n = 21 = 2 network
Host       = 2h-2 = 215-2 = 32.766 host

Alokasi IP :
Network   :10.168.0.0
Host         : 10.168.0.1 - 10.168.127.254
Broadcast : 10.168.127.255